If your original system is set up for 12VDC devices, then that is what they will continue to require. If you give those devices 48VDC, you will likely destroy anything you energise.
The D40 is primarily a multi chemistry battery charger, however, if you set to load mode it outputs 12VDC @ 20A and then can be connected to you 12VDC fuse box.
You definitely need the D40 to use the 48VDC port of the 200L.
@KKS There is no definitive correct answer as it depends on what your set up is.
The output limit of the D40 in power supply mode is 12V @ 20A. If you want to be able to draw this load, those are your parameters. The unknown qty is the length of cable run between the D40 output and the load. Including fuse block.
If you Google “voltage drop calculator” input the V, A, cable gauge and cable length (that is the total length of the + & - wires). The answer will be voltage drop and most sources look for less than 3%. If it’s more than 3% enter with the next thicker wire gauge and recalculate until it is less than 3%.
(Note - if the answer is a small voltage drop, you need to divide the voltage drop by the voltage (12V) and multiply by 100 to give %)